Validating XML against XSD in Java

To validate XML documents against XSD in java...


You can use the DocumentBuilderFactory or SAXParserFactory from http://java.sun.com/j2se/1.4.2/docs/api/javax/xml/parsers/package-summary.html

        String JAXP_SCHEMA_SOURCE = "http://java.sun.com/xml/jaxp/properties/schemaSource";
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        factory.setNamespaceAware(true);
        factory.setValidating(true);

        String schemaSource = "Path to your XSD";
        Source schemaSourceSrc = new StreamSource(schemaSource);        // has various constructors to pass xsd as a file,url,stream and so on ...
        SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
        Schema schema = schemaFactory.newSchema(schemaSourceSrc);
       
        factory.setSchema(schema);
        DocumentBuilder builder = factory.newDocumentBuilder();
        Document document = builder.parse(" your xml file ");

This will validate your xml file against the xsd. Many examples in the web show similar snippets...  More details are on the link below from sun

"http://java.sun.com/developer/technicalArticles/xml/validationxpath/"

Note: If your XSD document contains regular expressions or data type restrictions then they are also validated.